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ILTS-05 · Biology · Error notes

Inheritance, and Evolution

Two chapters, eighteen questions

Every biology question flagged on this paper, rebuilt in full. Each one carries what was given, what was asked, the concept behind it, the rule, the steps written out, a table justifying the right option and ruling out each of the others, the fastest route through, and an animated figure wherever seeing the thing settles the answer.

18Questions lost
16Attempted, wrong
2Left blank
80Marks at stake

The shape of this paper

Eighteen questions, and the split is stark: sixteen attempted and missed against only two left blank. That is an attempt rate of 89 per cent, far above anything in the earlier papers, and it is genuine progress — the reluctance to commit has largely gone.

What it exposes instead is accuracy. On NEET marking the sixteen wrong answers cost 64 marks in unearned scores plus 16 in negatives; the two blanks cost 8. The problem is no longer whether to answer, it is which answer.

And the sixteen are not sixteen separate gaps. They collapse into about five recurring confusions, which is a much smaller thing to fix than the raw number suggests.

Contents

Principles of Inheritance and Variation7 questions · 6 wrong · 1 blank
Q1Q2Q3Q8Q22Q27Q31
Evolution11 questions · 10 wrong · 1 blank
Q46Q51Q53Q55Q58Q74Q78Q81Q82Q83Q89
Red = attempted and missed · Amber = left blank

Principles of Inheritance and Variation

6 wrong · 1 blank

Seven questions, six of them attempted and missed. Two of the six turn on the same confusion between incomplete dominance and co-dominance; two more turn on which generation or which cross the question is actually describing.

Q 1Attempted · wrongIncomplete dominance · back-working a cross

In Snapdragon, a cross produces pink and white flowers in a 1:1 ratio. This result is obtained by crossing plants with which flower colours?

  1. Pink and pink.
  2. Her answerRed and white.
  3. CorrectPink and white.
  4. Red and pink.
Given
  • Snapdragon flower colour shows incomplete dominance.
  • RR = red, Rr = pink, rr = white.
  • The offspring appear as pink : white = 1 : 1.
Asked

The flower colours of the two parents.

Concept to use

In incomplete dominance every genotype has its own visible colour, so reading the offspring backwards is straightforward: pink offspring must be Rr and white offspring must be rr. A 1 : 1 ratio with only two classes is the signature of a test-cross pattern — one heterozygous parent crossed with one homozygote.

Diagram
Three ways a heterozygote can lookCOMPLETERR × rrF₁ = Rrlooks like ONE parentINCOMPLETERR × rrF₁ = Rra BLEND — in betweenCO-DOMINANCEIᵀIᵀ × IᴿIᴿF₁ = IᵀIᴿBOTH shown, side by sideA BLEND means incomplete dominance. BOTH parental traits appearingseparately in the same individual means co-dominance. They are not the same.
AnimatedThree dominance patterns, and what the heterozygote looks like in each.
Formula to useRr × rr → Rr : rr = 1 : 1 = pink : white
Baby steps
  1. No red offspring appear at all, so no RR is ever produced — which means at least one parent cannot supply a second R.
  2. White offspring (rr) appear, so both parents must be able to give an r.
  3. Pink offspring (Rr) appear, so one parent must be able to give an R.
  4. The only pair satisfying all three is Rr × rr — pink × white.
  5. Check: Rr × rr gives Rr, Rr, rr, rr = 2 pink : 2 white = 1 : 1. ✓
Answer
Pink and white
Why this option and not the others
OptionVerdictReason
Pink × pinkrule outRr × Rr gives 1 RR : 2 Rr : 1 rr = 1 red : 2 pink : 1 white. Red appears, and the ratio is 1:2:1, not 1:1.
Red × whiterule outRR × rr gives every offspring as Rr — all pink, no white at all. This is the F₁ cross, not the one described.
Pink × whitekeepRr × rr gives exactly 1 pink : 1 white, with no red. Matches the data on every point.
Red × pinkrule outRR × Rr gives 1 RR : 1 Rr = 1 red : 1 pink. The ratio is right but the colours are wrong — no white is produced.
Shortcut
Two rules crack every backward cross of this kind. A 1 : 1 ratio always means heterozygote × homozygote. And whichever phenotypes are missing from the offspring tell you what the parents could not supply. Here red is missing, so no parent could give a second R — which rules out three of the four options immediately.
Where it went wrong
Red × white gives all-pink offspring, which is the classic F₁ result and probably the cross that came to mind first. But it produces no white at all, so it cannot give 1 : 1. The habit that catches this is to test the chosen option forwards before moving on — a single Punnett square, ten seconds, and the mismatch is obvious.
Q 2Attempted · wrongTest cross · probability

When crossing an organism that is a heterozygote with a homozygous recessive for a single trait, what is the chance of producing an offspring with the homozygous recessive phenotype?

  1. 0%
  2. Her answer25%
  3. Correct50%
  4. 75%
Given
  • Parent 1 is heterozygous: Aa.
  • Parent 2 is homozygous recessive: aa.
  • A single trait, ordinary complete dominance.
Asked

The chance of an offspring with the homozygous recessive phenotype.

Concept to use

This is a test cross, and it behaves quite differently from the carrier × carrier cross. The recessive parent can only ever give an a, so every offspring already has one a guaranteed. The whole outcome then rests on the single gamete from the heterozygous parent: A gives Aa, a gives aa — a straight coin toss.

Diagram
gametes from one parentAaaaAaaaAaaagametesfrom the otherTwo boxes out of four are aa — half the offspring.
AnimatedThe test cross Aa × aa: only one parent varies, so the split is 1 : 1.
Formula to useAa × aa → Aa : aa = 1 : 1 → 50% recessive
Baby steps
  1. Heterozygote Aa makes two kinds of gamete in equal numbers: A and a.
  2. Homozygous recessive aa makes only one kind: a.
  3. Combining: A × a gives Aa, and a × a gives aa.
  4. So the offspring are 1 Aa : 1 aa.
  5. Recessive phenotype = aa = 1 in 2 = 50%.
Answer
50%
Why this option and not the others
OptionVerdictReason
0%rule outThe heterozygote can supply a recessive allele, and the other parent always does, so aa offspring certainly occur.
25%rule out25% is the answer for Aa × Aa — two heterozygotes. Here the second parent is aa, which changes everything.
50%keepOnly one parent varies, so the outcome is a straight 1 : 1 split.
75%rule out75% is the fraction showing the dominant phenotype in an Aa × Aa cross. Wrong cross and wrong phenotype.
Shortcut
When one parent is homozygous, that parent contributes nothing to the variation — it always sends the same allele. So count only the gametes of the other parent. A heterozygote makes two kinds equally, so the answer is 50%. This is why the test cross works as a tool: the ratio in the offspring is a direct readout of the unknown parent's gametes.
Where it went wrong
25% is the answer to the other standard cross, Aa × Aa, which appeared on the previous ILTS paper as the phenylketonuria question and was correct there. The two crosses look almost identical on the page and give different answers, so the distinguishing step has to be deliberate: read the second parent first. If it is homozygous, the answer is 50% or 0%; if it is heterozygous, it is 25% or 75%.
Q 3Attempted · wrongLaw of segregation

In the principles of inheritance, law of segregation is based on the fact that

  1. CorrectThe alleles do not show any blending and the alleles/traits are recovered in the next generation.
  2. The alleles of a trait always remain together, but only one of them can express its character.
  3. The alleles of a trait never come together and they express their characters separately.
  4. Her answerAll alleles of a trait lie on the same chromosome and they segregate during crossing over.
Given
  • Mendel's law of segregation.
  • Four candidate statements of what the law rests on.
Asked

The fact on which the law of segregation is based.

Concept to use

Segregation says that the two alleles of a gene sit together in a diploid organism but separate cleanly during gamete formation, so each gamete gets one and only one. The observational fact that forces this conclusion is what happens in F₂: the recessive trait, invisible throughout F₁, reappears unchanged. It was never diluted or blended — it was simply hidden and then recovered.

Diagram
gametes from one parentTtTtTTTtTtttgametesfrom the otherThe recessive tt returns intact — it was hidden, never blended.
AnimatedF₂ of a monohybrid cross: the recessive is recovered unchanged.
Formula to useAa → gametes A and a, never Aa → recessive reappears intact in F₂
Baby steps
  1. In F₁ the hybrid Aa looks entirely like the dominant parent, so a blending theory would predict the recessive character is lost or diluted.
  2. In F₂ the recessive character comes back looking exactly as it did in the original parent — not faded, not intermediate.
  3. That can only happen if the two alleles stayed separate and unaltered while together, then parted during gamete formation.
  4. So the law rests on no blending, and recovery in the next generation.
Answer
The alleles do not show any blending and the alleles/traits are recovered in the next generation
Why this option and not the others
OptionVerdictReason
no blending, recovered laterkeepThis is exactly what F₂ demonstrates, and it is the observation that killed the blending theory of inheritance.
always remain together, one expressesrule outThe first half is wrong: alleles separate during gamete formation — that is the whole point of segregation. The second half describes dominance, a different law.
never come togetherrule outAlso wrong: in a diploid the two alleles most certainly are together. They separate only when gametes form.
same chromosome, segregate at crossing overrule outTwo errors. The two alleles of one gene lie on homologous chromosomes, not the same one. And they separate at anaphase I of meiosis, not through crossing over.
Shortcut
Each of Mendel's laws has one signature word. Dominance is about which allele shows. Segregation is about alleles separating into gametes. Independent assortment is about two different genes behaving independently. Match the option to the signature word and three of the four usually fall away.
Where it went wrong
The chosen option puts both alleles of one gene on the same chromosome, and then makes crossing over do the separating. Both halves are wrong, and they are wrong in a related way: alleles of a single gene occupy the same locus on the two homologous chromosomes, so they are pulled apart when the homologues separate at anaphase I. Crossing over exchanges segments between homologues and is the mechanism behind recombination, not segregation. Worth noting that this is a mechanism question dressed as a definition question — and the mechanism is the part that slipped.
Q 8Attempted · wrongIncomplete dominance · starch grain size

If size of starch grains in pea is considered as phenotype, Bb alleles show

  1. Her answerco-dominance
  2. dominance
  3. Correctincomplete dominance
  4. pleiotropism
Given
  • Pea seed starch grains, gene B.
  • BB produces large starch grains, bb produces small ones.
  • The heterozygote is Bb.
Asked

What kind of dominance Bb shows when starch grain size is the phenotype.

Concept to use

The same gene can show different dominance relationships depending on which phenotype you look at. Judged by seed shape, Bb peas are round like BB — complete dominance. But judged by starch grain size, Bb grains are intermediate: bigger than bb, smaller than BB. An intermediate heterozygote is the definition of incomplete dominance.

Diagram
Three ways a heterozygote can lookCOMPLETERR × rrF₁ = Rrlooks like ONE parentINCOMPLETERR × rrF₁ = Rra BLEND — in betweenCO-DOMINANCEIᵀIᵀ × IᴿIᴿF₁ = IᵀIᴿBOTH shown, side by sideA BLEND means incomplete dominance. BOTH parental traits appearingseparately in the same individual means co-dominance. They are not the same.
AnimatedA blend is incomplete dominance; both traits together is co-dominance.
Formula to useBB (large) > Bb (INTERMEDIATE) > bb (small) → incomplete dominance
Baby steps
  1. BB seeds have large starch grains; bb seeds have small ones.
  2. Bb seeds have grains of intermediate size — a blend, not a copy of either parent.
  3. A heterozygote showing a blend is incomplete dominance.
  4. Note the contrast: for seed shape, Bb is fully round like BB, so the same gene shows complete dominance on that phenotype. Dominance is a property of the phenotype you choose to measure, not of the gene alone.
Answer
Incomplete dominance
Why this option and not the others
OptionVerdictReason
co-dominancerule outCo-dominance means both parental phenotypes appear separately and fully in the same individual — like the AB blood group, where both A and B antigens are present. Intermediate-sized grains are a blend, not two distinct types side by side.
dominancerule outThis is true for seed shape but not for grain size. The stem specifies size.
incomplete dominancekeepThe heterozygote is intermediate between the two homozygotes — the textbook definition.
pleiotropismrule outPleiotropy is one gene affecting several unrelated traits. It is genuinely relevant to this gene — B affects both shape and starch — but it is not what the question asks about the Bb relationship.
Shortcut
The distinction between the two tempting options comes down to a single question: is the heterozygote a mixture, or a mosaic? A mixture — pink between red and white, medium between large and small — is incomplete dominance. A mosaic, both parental types visible separately and unchanged, is co-dominance. Blends blend; co-dominants coexist.
Where it went wrong
Co-dominance and incomplete dominance are the pair this chapter tests most often, and the line between them is exactly the blend-versus-both distinction. An intermediate grain size is one new value in between, not two original values appearing together, so it is a blend. Note that this same pair reappears as Q31 on this paper, where options I and III had to be told apart on the same grounds — and the same two were swapped there. That makes it one confusion costing two questions.
Q 22Attempted · wrongTrue-breeding cross · the F₁ generation

A true breeding violet-flowered garden pea plant is crossed with a white-flowered garden pea plant. What is the expected ratio of violet and white-flowered plants in the offspring?

  1. Correct1 violet flowered : 0 white flowered
  2. Her answer3 violet flowered : 1 white flowered
  3. 0 violet flowered : 1 white flowered
  4. 1 violet flowered : 1 white flowered
Given
  • A true-breeding violet-flowered pea: VV.
  • A white-flowered pea: vv (white is recessive, so white plants are always homozygous).
  • Violet is completely dominant over white.
Asked

The ratio of violet to white in the offspring of this cross.

Concept to use

Two words decide this. True-breeding means homozygous, so the violet parent is VV, not Vv. And offspring means the immediate next generation, F₁ — not F₂. A VV × vv cross can only produce Vv, and every Vv plant is violet.

Diagram
gametes from one parentVVvvVvVvVvVvgametesfrom the otherEvery box is Vv, and every Vv is violet. Ratio 1 : 0.
AnimatedVV × vv: the F₁ generation is completely uniform.
Formula to useVV × vv → all Vv → 100% violet = 1 : 0
Baby steps
  1. True-breeding violet gives only V gametes.
  2. White is recessive, so a white plant must be vv and gives only v gametes.
  3. Every offspring is therefore Vv.
  4. Vv is violet, since violet is completely dominant.
  5. All offspring are violet: the ratio is 1 : 0.
Answer
1 violet : 0 white
Why this option and not the others
OptionVerdictReason
1 : 0keepEvery F₁ plant is Vv and therefore violet. No white appears in this generation at all.
3 : 1rule outThis is the F₂ ratio, obtained by selfing the F₁. The question stops one generation earlier.
0 : 1rule outThis would need the violet parent to contribute no V, which contradicts true-breeding violet.
1 : 1rule outThis is the test-cross ratio, Vv × vv. It would apply if the violet parent were heterozygous — but true-breeding rules that out.
Shortcut
Count the generations in the stem. One cross described means F₁, and F₁ from two true-breeding parents is always uniform — 100% of the dominant type, ratio 1 : 0. The famous 3 : 1 needs a second step, the selfing of F₁, and the question has to say so. If you see only one cross, 3 : 1 is not available.
Where it went wrong
3 : 1 is the most famous ratio in the chapter, and it is the F₂ ratio. The question describes a single cross, which produces F₁ only. This is a generation-counting error rather than a genetics error — the underlying understanding of dominance is intact, and the fix is to circle the word “offspring” and ask of which cross? before reaching for a remembered ratio.
Q 27Left blankF₂ · counting TYPES, not individuals

In a pea plant, Mendel obtained the ratio between the types of phenotypes and genotypes in F₂ generation of monohybrid cross is

  1. Correct2:3
  2. 1 : 2 : 1
  3. 3:1
  4. 1:1
Given
  • A monohybrid cross, F₂ generation.
  • Phenotypic ratio in F₂ = 3 : 1.
  • Genotypic ratio in F₂ = 1 : 2 : 1.
Asked

The ratio between the number of types of phenotypes and the number of types of genotypes.

Concept to use

This question is not asking for either of the two famous ratios — it is asking how many different kinds there are of each. In F₂ of a monohybrid cross there are two phenotypes (tall and dwarf) and three genotypes (TT, Tt, tt). So the answer is a count of categories, 2 : 3, not a count of individuals.

Diagram
gametes from one parentTtTtTTTtTtttgametesfrom the other3 genotype TYPES (TT, Tt, tt) against 2 phenotype TYPES.
AnimatedCount the distinct kinds in each row, not the number of individuals.
Formula to usephenotype TYPES = 2 (3 : 1) genotype TYPES = 3 (1 : 2 : 1) ratio = 2 : 3
Baby steps
  1. Write out the F₂ genotypes: TT, Tt, Tt, tt.
  2. How many different genotypes? TT, Tt, tt — that is 3 types.
  3. How many different phenotypes? Tall and dwarf — that is 2 types.
  4. The stem asks for phenotypes : genotypes, in that order.
  5. Ratio = 2 : 3.
Answer
2 : 3
Why this option and not the others
OptionVerdictReason
2:3keepTwo kinds of phenotype against three kinds of genotype. This is a count of categories, which is what “the types of” means.
1 : 2 : 1rule outThe genotypic ratio itself — the numbers of individuals, not the number of kinds.
3:1rule outThe phenotypic ratio itself. Again individuals, not kinds.
1:1rule outNeither a Mendelian ratio for F₂ nor a count of types.
Shortcut
The tell is the phrase “the ratio between the types of”. Whenever a stem says types, kinds or classes, stop and count categories rather than reaching for a remembered ratio. Two of the four options here are simply the two famous ratios, offered precisely because they are what the eye jumps to.
Q 31Attempted · wrongMatch · dominance patterns and Mendel's laws

Match the following genetic concepts (List I) with their features/examples (List II).
A. Complete Dominance   I. F₁ shows an intermediate phenotype
B. Incomplete Dominance   II. Each allele separates during gamete formation
C. Co-dominance   III. F₁ shows both parental traits
D. Law of Segregation   IV. F₁ shows only the dominant trait

  1. CorrectA – IV, B – I, C – III, D – II
  2. A – III, B – IV, C – I, D – II
  3. A – I, B – II, C – III, D – IV
  4. Her answerA – IV, B – III, C – I, D – II
Given
  • Four concepts: complete dominance, incomplete dominance, co-dominance, law of segregation.
  • Four features describing what F₁ looks like, plus one about gamete formation.
Asked

The correct matching.

Concept to use

Three of the four are about what the heterozygote looks like, and they form a clean progression. Complete dominance: F₁ looks like one parent only. Incomplete dominance: F₁ looks like a blend of the two. Co-dominance: F₁ shows both parental traits, fully and separately. The fourth, segregation, is the odd one out — it is about gametes, not appearance, and it pairs with the only option mentioning gametes.

Diagram
Three ways a heterozygote can lookCOMPLETERR × rrF₁ = Rrlooks like ONE parentINCOMPLETERR × rrF₁ = Rra BLEND — in betweenCO-DOMINANCEIᵀIᵀ × IᴿIᴿF₁ = IᵀIᴿBOTH shown, side by sideA BLEND means incomplete dominance. BOTH parental traits appearingseparately in the same individual means co-dominance. They are not the same.
AnimatedThe three dominance patterns side by side, which is what List II describes.
Formula to useone parent → complete · a blend → incomplete · both → co-dominance
Baby steps
  1. D first, because it is the easiest. Law of segregation is the only concept about gametes, and II is the only feature about gametes. D – II.
  2. A. Complete dominance — the heterozygote shows only the dominant trait. A – IV.
  3. B. Incomplete dominance — the heterozygote is intermediate, a blend. B – I.
  4. C. Co-dominance — the heterozygote shows both parental traits at once. C – III.
  5. Answer: A – IV, B – I, C – III, D – II.
Answer
A – IV, B – I, C – III, D – II
Why this option and not the others
OptionVerdictReason
A-IV, B-I, C-III, D-IIkeepEach concept sits with its own definition; the blend goes to incomplete and both-traits goes to co-dominance.
A-III, B-IV, C-I, D-IIrule outPuts “both parental traits” on complete dominance, which is the opposite of what complete dominance means.
A-I, B-II, C-III, D-IVrule outMatches segregation to “only the dominant trait”, which is a dominance statement, not a segregation one.
A-IV, B-III, C-I, D-IIrule outA and D are right, but B and C are swapped: intermediate belongs to incomplete dominance and both-traits to co-dominance.
Shortcut
In any matching question, do the odd one out first. Here three items are about appearance and one is about gametes, so D – II is free and instantly narrows the field. Then remember the one-word test for the remaining pair: intermediate is incomplete, both is co-dominance.
Where it went wrong
A and D were placed correctly, so the structure of the question was understood. B and C were swapped — incomplete dominance was given “both parental traits” and co-dominance was given “intermediate”. This is the same confusion as Q8 on this paper, where co-dominance was chosen for an intermediate starch grain size. One mixed-up pair cost two questions and 10 marks. Fixing that single distinction is the highest-value thing in this chapter.

Evolution

10 wrong · 1 blank

Eleven questions, ten of them attempted and missed. Three of the ten are the same homologous-versus-analogous distinction asked three different ways, and three more are pure recall — dates and names, with no reasoning available.

Q 46Attempted · wrongMiller's experiment · the gases

Which of the following gases were used in the spark chamber of Miller's simulation experiment?

  1. Her answerCH₄, H₂, NH₃, CO₂
  2. CorrectCH₄, H₂O, NH₃, H₂
  3. H₂, O₂, CH₄, NH₃
  4. H₂O, C₂H₅OH, NH₃
Given
  • Stanley Miller's 1953 simulation of the early earth.
  • The chamber was meant to reproduce the primitive reducing atmosphere.
Asked

Which gases were placed in the spark chamber.

Concept to use

Miller was trying to recreate an atmosphere with no free oxygen — a reducing one, in which hydrogen is abundant. The four things he sealed in were methane, ammonia, hydrogen and water vapour, with electric discharges at 800 °C standing in for lightning. After a week the condensed liquid contained amino acids.

Diagram
Miller and Urey, 1953CH₄ H₂NH₃ H₂O800 °C sparkspark chamber = the early atmospherecondensedand trappedamino acids formedThe gases were the REDUCING atmosphere of the early earth — methane,hydrogen, ammonia and water vapour. There was no free oxygen, andno CO₂ in Miller's chamber.
AnimatedThe spark chamber and the four gases sealed inside it.
Formula to useCH₄ + NH₃ + H₂ + H₂O + spark → amino acids
Baby steps
  1. The early atmosphere had no free oxygen — that rules out any option containing O₂ at once.
  2. It was reducing, i.e. rich in hydrogen, so H₂ must be present.
  3. The carbon came in as methane, not as carbon dioxide, since CO₂ is an oxidised form of carbon.
  4. Water vapour supplied the oxygen and hydrogen for the amino acids.
  5. So the set is CH₄, H₂O, NH₃, H₂.
Answer
CH₄, H₂O, NH₃, H₂
Why this option and not the others
OptionVerdictReason
CH₄, H₂, NH₃, CO₂rule outCO₂ is oxidised carbon and does not belong in a reducing atmosphere; and water vapour, which was definitely present, is missing.
CH₄, H₂O, NH₃, H₂keepThe four gases Miller actually used — all reduced forms, no free oxygen.
H₂, O₂, CH₄, NH₃rule outContains free O₂, which is exactly what the early atmosphere lacked. Oxygen would have destroyed the organic molecules as they formed.
H₂O, C₂H₅OH, NH₃rule outEthanol is already an organic molecule. Putting it in would defeat the purpose of the experiment, which was to make organics from inorganics.
Shortcut
One word carries the whole question: reducing. That means hydrogen-rich and oxygen-free, so cross out anything with O₂ and anything with carbon in an oxidised form like CO₂. Two options die on that test alone, and a third dies because ethanol is organic. The four gases are worth memorising as a single unit — methane, ammonia, hydrogen, water vapour.
Where it went wrong
The chosen option swaps water vapour for CO₂. It keeps three of the four right, so the general picture was correct, but CO₂ is an oxidised carbon compound and its presence contradicts the reducing atmosphere the experiment was designed around. Water vapour, meanwhile, is not optional — it is what condenses and carries the amino acids into the trap.
Q 51Attempted · wrongArtificial selection

Most modern breeds of domestic dog have evolved by

  1. Her answernatural selection
  2. Correctartificial selection
  3. sexual selection
  4. temporal isolation
Given
  • Modern breeds of domestic dog.
  • They descend from wolf ancestors over a few thousand years.
Asked

The process by which they arose.

Concept to use

The question turns on who did the choosing. In natural selection the environment decides which individuals survive and reproduce. In artificial selection humans decide — picking the animals with the traits they want and breeding from those. Every dog breed exists because people chose the parents, generation after generation.

Diagram
ARTIFICIAL selectionHUMANS choose who breedsdog breeds · cabbage,broccoli and kale fromone wild mustardNATURAL selectionthe ENVIRONMENT decidespeppered moth ·antibiotic resistance ·Darwin's finchesa human hand choseno one choseA chihuahua and a great dane exist because PEOPLE bred them that way.No wild pressure would produce either. That makes it artificial selection.
AnimatedWho did the choosing — the environment, or a person?
Formula to useenvironment chooses → NATURAL humans choose → ARTIFICIAL
Baby steps
  1. Ask what would happen to a chihuahua or a dachshund in the wild. Neither would be favoured by any natural pressure.
  2. These forms exist because breeders selected them deliberately for size, coat, temperament or working ability.
  3. Human-directed selection is artificial selection.
  4. Darwin used exactly this — domestic pigeons and dogs — as his everyday illustration of how selection works, before arguing that nature does the same thing unaided.
Answer
Artificial selection
Why this option and not the others
OptionVerdictReason
natural selectionrule outThe environment did not favour these forms; humans did. In the wild most breeds would fare badly.
artificial selectionkeepHumans chose which dogs bred, generation after generation. This is the textbook example, along with cabbage, broccoli and kale from wild mustard.
sexual selectionrule outSexual selection is mate choice by the animals themselves — peacock tails, stag antlers. Domestic dogs are generally not choosing their own mates.
temporal isolationrule outThis is a mechanism of speciation — two populations breeding at different times of year. It is not a selection process at all.
Shortcut
Whenever a question names something domesticated — dogs, cattle, crop plants, pigeons — the answer is artificial selection. The word “domestic” in the stem is doing the work.
Where it went wrong
Natural and artificial selection use the same mechanism, so choosing the wrong one is understandable — but the distinguishing question is a single one: did a human make the choice? Here the stem says “domestic”, which answers it directly. This is the second question on this paper (with Q22) where the deciding word was present in the stem and was read past.
Q 53Attempted · wrongHomologous organs

Which of the following are considered homologous organs?

  1. CorrectVertebrate hearts and brains
  2. Eyes of squids and of mammals
  3. Limbs of arthropods and frogs
  4. Her answerVertebrate hearts and insect hearts
Given
  • Four pairs of organs from different animals.
Asked

Which pair is homologous.

Concept to use

Homologous organs share the same basic structural plan inherited from a common ancestor, even if they now do different jobs. Analogous organs are the reverse: different structural plans that arrived at the same job because of similar pressures. The quick test is whether the two animals belong to the same major group. Homology usually sits inside a group; analogy usually crosses between groups.

Diagram
HOMOLOGOUSsame structure, different jobfrom a COMMON ANCESTORDIVERGENT evolutionwhale flipper · bat winghuman arm · vertebrate heartsANALOGOUSdifferent structure, same jobfrom SIMILAR PRESSURESCONVERGENT evolutionbird wing · insect wingseal flipper · penguin flipperone ancestor, many formsmany ancestors, one formAsk ONE question: do they share an ancestor, or just a job?Homologous pairs sit inside the same group. Analogous pairs cross groups.
AnimatedShared ancestor, or shared job? The one question that decides both.
Formula to usesame ancestor, structure shared → HOMOLOGOUS (divergent)
Baby steps
  1. All vertebrates — fish, amphibians, reptiles, birds, mammals — share a common ancestor.
  2. Their hearts follow one basic plan, modified from two chambers to four; their brains likewise share fore-, mid- and hindbrain divisions.
  3. So vertebrate hearts (across vertebrates) and vertebrate brains are both homologous sets — same plan, common ancestry, varying detail.
  4. The other three pairs each cross between unrelated groups, which makes them analogous.
Answer
Vertebrate hearts and brains
Why this option and not the others
OptionVerdictReason
Vertebrate hearts and brainskeepBoth are structures shared across the vertebrates by descent from a common ancestor, varying in form but built on one plan.
Eyes of squids and of mammalsrule outThe classic analogy: a mollusc eye and a vertebrate eye do the same job with quite different construction and separate evolutionary origins.
Limbs of arthropods and frogsrule outAn arthropod limb has an external skeleton and a frog limb an internal one — different plans, no shared limb ancestry. Analogous.
Vertebrate hearts and insect heartsrule outAn insect heart is a simple dorsal tube pumping haemolymph in an open system. It shares no structural plan with a vertebrate heart. Analogous.
Shortcut
Run one test on the pair: do these two animals belong to the same major group? Vertebrate-and-vertebrate is a homology candidate. Squid-and-mammal, arthropod-and-frog, insect-and-vertebrate all cross between phyla and are therefore analogies. Three of the four options here fail on that single check.
Where it went wrong
Insect hearts and vertebrate hearts do the same job, and same-job is exactly the definition of analogous, not homologous. The two words were applied the wrong way round. Note that Q55 and Q81 on this same paper turn on the identical distinction and were also answered with “homologous” — three questions, twelve marks, one definition.
Q 55Attempted · wrongAnalogous organs

Flippers of seals and penguins are an example of

  1. Her answerhomologous organs
  2. Correctanalogous organs
  3. atavistic organs
  4. vestigial organs
Given
  • A seal is a mammal; a penguin is a bird.
  • Both have flipper-shaped limbs used for swimming.
Asked

What kind of organs these flippers are.

Concept to use

Both animals swim, and water imposes the same demands whatever your ancestry: a flat, paddle-like limb. A seal's flipper is a modified mammalian forelimb; a penguin's is a modified bird wing. Two different starting structures pushed into the same shape by the same environment is convergent evolution, and the resulting organs are analogous.

Diagram
HOMOLOGOUSsame structure, different jobfrom a COMMON ANCESTORDIVERGENT evolutionwhale flipper · bat winghuman arm · vertebrate heartsANALOGOUSdifferent structure, same jobfrom SIMILAR PRESSURESCONVERGENT evolutionbird wing · insect wingseal flipper · penguin flipperone ancestor, many formsmany ancestors, one formAsk ONE question: do they share an ancestor, or just a job?Homologous pairs sit inside the same group. Analogous pairs cross groups.
AnimatedSeal and penguin sit in different classes, so the flippers are analogous.
Formula to usedifferent ancestry + same job → ANALOGOUS (convergent)
Baby steps
  1. Identify the groups: seal = mammal, penguin = bird. Different classes.
  2. Identify the job: both flippers are for swimming. Same function.
  3. Different origin plus same function = analogous.
  4. The underlying cause is convergent evolution — similar environments producing similar solutions independently.
Answer
Analogous organs
Why this option and not the others
OptionVerdictReason
homologous organsrule outHomology would require a shared flipper-bearing ancestor. The last common ancestor of birds and mammals had no flippers at all.
analogous organskeepSame function, different structural origin, arrived at independently — the definition of analogy.
atavistic organsrule outAn atavism is the reappearance of an ancestral feature that had been lost — a human born with a tail. Flippers are not reappearances.
vestigial organsrule outA vestigial organ is a reduced, functionless remnant — the human appendix, the vermiform coccyx. These flippers are fully functional and essential.
Shortcut
Note the trap built into the phrasing. A seal's flipper and a whale's flipper would be homologous, since both are mammals. Swapping the whale for a penguin changes the answer entirely. So read the two animals before reading the organ — the classes decide it, not the shape.
Where it went wrong
The flippers look alike, and that similarity is precisely what the question is testing. Looking alike is evidence of analogy when the animals are unrelated. The single question that resolves it — are these two animals in the same class? — would have given bird and mammal, and therefore analogous. This is the same slip as Q53 and Q81.
Q 58Attempted · wrongAge of the universe
Worth knowing the sources disagreeThis paper marks 13.8 billion years correct, which is the modern astrophysical figure. NCERT Class XII still prints “the universe is very old — almost 20 billion years old”, which is the option chosen. So the answer given was the NCERT answer, and it was marked wrong against a scientifically updated key. Carry both numbers and take the paper's cue.

The age of the universe is approximately

  1. 4.5 billion years
  2. Correct13.8 billion years
  3. Her answer20 billion years
  4. 65 million years
Given
  • Standard dates from the Evolution chapter.
Asked

The approximate age of the universe.

Concept to use

The chapter uses four landmark dates and they get shuffled between questions, so they are best learned as one set rather than one at a time: the universe forms, the earth forms, the first cellular life appears, and the dinosaurs die out. Only the first of these is asked here.

Diagram
13.8 byauniverse forms4.5 byaearth forms2000 myafirst cellular life65 myadinosaurs die outThe four dates the chapter keeps asking foroldertodayCareful: NCERT still prints “almost 20 billion years” for the universe,while the modern astrophysical figure is 13.8 billion. Papers differ.
AnimatedThe four landmark dates, with the NCERT discrepancy noted.
Formula to useuniverse 13.8 bya · earth 4.5 bya · first cells 2000 mya · dinosaurs out 65 mya
Baby steps
  1. The Big Bang is dated by the cosmic microwave background and the expansion rate.
  2. The current accepted figure is 13.8 billion years.
  3. 4.5 billion is the age of the earth, not the universe — the commonest confusion in this set.
  4. 65 million years is when the dinosaurs disappeared, a vastly more recent event.
Answer
13.8 billion years (see the note above on NCERT's figure)
Why this option and not the others
OptionVerdictReason
4.5 billionrule outThe age of the earth. Right number, wrong object — and it is the most frequently offered distractor in this question.
13.8 billionkeepThe modern astrophysical value, and the one this paper's key uses.
20 billionrule outMarked incorrect here, but it is the figure printed in NCERT. See the note at the top of this card — this is a genuine textbook-versus-science disagreement, not a mistake in reasoning.
65 millionrule outThe end of the Cretaceous and of the dinosaurs. Off by a factor of about two hundred.
Shortcut
Learn the four dates as one ladder, biggest to smallest, and most questions in this cluster become a lookup: 13.8 billion → 4.5 billion → 2000 million → 65 million. Note the unit switch halfway down — billions become millions — which is where the errors usually creep in.
Where it went wrong
This one is not really an error. The option chosen, 20 billion, is what NCERT states, and answering from the prescribed textbook is normally the right instinct for NEET. The paper has used the updated scientific value instead. The useful takeaway is to know both numbers and which source each belongs to: if an option list offers 13.8 and does not offer 20, take 13.8; if it offers both, the paper is deliberately testing this, and 13.8 is the safer modern choice.
Q 74Attempted · wrongEmbryological evidence

Embryological support for evolution was proposed by

  1. Lamarck
  2. Her answerCharles Darwin
  3. Alfred Wallace
  4. CorrectErnst Haeckel
Given
  • The embryological line of evidence for evolution.
Asked

Who proposed it.

Concept to use

Ernst Haeckel observed that vertebrate embryos of different species pass through similar stages, and proposed that an embryo repeats its evolutionary history as it develops — his “biogenetic law”. The classic example is the gill slits present in the embryos of all vertebrates, including humans. NCERT also notes that this was later disproved by Karl Ernst von Baer, who showed embryos never pass through the adult stages of other animals.

Diagram
Miller and Urey, 1953CH₄ H₂NH₃ H₂O800 °C sparkspark chamber = the early atmospherecondensedand trappedamino acids formedThe gases were the REDUCING atmosphere of the early earth — methane,hydrogen, ammonia and water vapour. There was no free oxygen, andno CO₂ in Miller's chamber.
AnimatedMiller's apparatus — a reminder of which name goes with which experiment.
Formula to useHaeckel: embryology as evidence → von Baer: the recapitulation claim disproved
Baby steps
  1. The claim is that embryonic development retraces evolutionary ancestry.
  2. Its author is Ernst Haeckel.
  3. The evidence cited is the set of features shared by early vertebrate embryos, such as gill slits.
  4. NCERT then records that von Baer disproved the strong form of the claim — a detail that is itself examined, so keep both names attached to this topic.
Answer
Ernst Haeckel
Why this option and not the others
OptionVerdictReason
Lamarckrule outLamarck is associated with the inheritance of acquired characters — the giraffe's neck — not with embryology.
Charles Darwinrule outDarwin proposed natural selection and gathered many lines of evidence, but the embryological argument is Haeckel's. Darwin is the default answer to any evolution question, which is exactly why he is offered here.
Alfred Wallacerule outWallace arrived at natural selection independently and studied the Malay Archipelago. Not embryology.
Ernst HaeckelkeepAuthor of the biogenetic law, and the name NCERT attaches to embryological support for evolution.
Shortcut
Attach one name to one idea and keep the pairs tight: Lamarck — acquired characters. Darwin and Wallace — natural selection. Haeckel — embryology. von Baer — the man who disproved Haeckel. Miller and Urey — chemical evolution. When Darwin appears as an option in a question about a specific line of evidence, be suspicious: he is the most attractive wrong answer in the whole chapter.
Where it went wrong
Darwin is the name most strongly associated with evolution, so he is the natural first reach — and papers exploit that. The specific attribution here is Haeckel's. Names in this chapter are pure recall with no reasoning available, which makes them worth a dedicated ten-minute memorisation pass rather than an attempt to work out in the exam hall.
Q 78Attempted · wrongDarwin's finches · the ancestral form

Which type of finch is considered the original ancestor of Darwin's finches?

  1. Insect eater
  2. Cactus eater
  3. CorrectSeed eater
  4. Her answerWoodpecker
Given
  • Darwin's finches of the Galapagos islands.
  • They now occupy many feeding niches: seeds, insects, cactus, and a tool-using woodpecker-like form.
Asked

Which type was the original ancestral form.

Concept to use

A small population of seed-eating ground finches reached the Galapagos from the mainland. With many empty niches and no competition, their descendants diversified into forms with quite different beaks — insect eaters, cactus feeders, a woodpecker-like finch. That process, one ancestral stock radiating into many forms in a new place, is adaptive radiation.

Diagram
Darwin's finches: one arrival, many beaksSEED-EATINGground finchinsect eatercactus eaterwoodpecker finchwarbler finchThe original stock was a seed eater. On the Galapagos it radiated intomany beak forms — ADAPTIVE RADIATION, and evidence for evolution.
AnimatedOne seed-eating ancestor, radiating into many specialists.
Formula to useone seed-eating ancestor → many beak forms = ADAPTIVE RADIATION
Baby steps
  1. The founding birds were ordinary mainland seed eaters.
  2. On reaching the islands they found many unoccupied feeding niches.
  3. Over generations, beak form diversified to exploit those niches.
  4. The specialised forms — insect eater, cactus eater, woodpecker finch — are the results of the radiation, not its starting point.
Answer
Seed eater
Why this option and not the others
OptionVerdictReason
Insect eaterrule outA derived form, produced by the radiation.
Cactus eaterrule outAlso derived — a specialist that could only arise once the birds were on the islands.
Seed eaterkeepThe ancestral ground finch. Seed eating is the generalist starting condition from which the specialists diverged.
Woodpeckerrule outThe woodpecker finch is the most specialised of all — it uses a cactus spine as a tool. A highly specialised form is the least likely candidate for an ancestor.
Shortcut
In any adaptive radiation question, the ancestor is the generalist and the descendants are the specialists. So look down the option list for the least specialised item and pick it. The woodpecker finch, being the most specialised of the four, is the least likely ancestor on that principle alone — you can reason to the answer without recalling the fact.
Where it went wrong
The woodpecker finch is the most memorable of Darwin's finches because of the tool use, which is probably why it came to mind. But memorability and ancestry point in opposite directions here: the striking specialist is the end of a radiation, never its beginning. The general principle — radiations run from generalist to specialist — would have given the answer without needing the specific fact.
Q 81Attempted · wrongAnalogy and convergent evolution together

The wings of a bird and the wings of an insect are

  1. homologous structures and represent convergent evolution
  2. Her answerhomologous structures and represent divergent evolution
  3. Correctanalogous structures and represent convergent evolution
  4. phylogenetic structures and represent divergent evolution
Given
  • A bird wing: a modified vertebrate forelimb, with bones.
  • An insect wing: an outgrowth of the body wall, with no bones at all.
  • Both are used for flight.
Asked

What kind of structures they are, and which pattern of evolution they represent.

Concept to use

Two labels have to be got right and they always travel together. Analogous structures — different construction, same function — are the product of convergent evolution, where unrelated lineages are pushed towards the same solution. Homologous structures — same construction, different functions — are the product of divergent evolution, where one ancestral plan is modified in different directions.

Diagram
HOMOLOGOUSsame structure, different jobfrom a COMMON ANCESTORDIVERGENT evolutionwhale flipper · bat winghuman arm · vertebrate heartsANALOGOUSdifferent structure, same jobfrom SIMILAR PRESSURESCONVERGENT evolutionbird wing · insect wingseal flipper · penguin flipperone ancestor, many formsmany ancestors, one formAsk ONE question: do they share an ancestor, or just a job?Homologous pairs sit inside the same group. Analogous pairs cross groups.
AnimatedThe labels travel in pairs: analogous with convergent, homologous with divergent.
Formula to useanalogous → convergent homologous → divergent
Baby steps
  1. Compare construction: a bird wing has humerus, radius, ulna and digits; an insect wing is a thin extension of the cuticle with no skeleton inside.
  2. Completely different construction, so not homologous.
  3. Same function, flight, arrived at independently: analogous.
  4. Analogy is always the signature of convergent evolution.
Answer
Analogous structures representing convergent evolution
Why this option and not the others
OptionVerdictReason
homologous + convergentrule outA mismatched pair — homology never goes with convergence. The two labels are locked together.
homologous + divergentrule outThe pairing is internally consistent, but the first label is wrong: birds and insects share no winged ancestor.
analogous + convergentkeepDifferent construction, same job, independent origin — analogy, and therefore convergence.
phylogenetic + divergentrule out“Phylogenetic structures” is not a recognised category. An invented term in an option list is almost always a filler.
Shortcut
Because the two labels are locked together, half the options in any question of this shape are internally inconsistent and can be crossed out without looking at the animals at all. Here that removes the homologous-convergent pairing straight away. Then one glance at construction — bones or no bones — settles the rest.
Where it went wrong
Both labels were chosen wrongly, but consistently: homologous-with-divergent is a valid pairing, just not the right one for this animal pair. So the relationship between the two terms is understood; what failed is the same structure-versus-function test as in Q53 and Q55. Three questions on this paper, twelve marks, and one distinction to fix: do they share an ancestor, or just a job?
Q 82Attempted · wrongMarsupials · the odd one out

Which of the following is not a marsupial?

  1. Numbat
  2. Her answerKoala
  3. Wombat
  4. CorrectLemur
Given
  • Four mammals.
  • Marsupials are pouched mammals, and Australia's adaptive radiation of them is the standard NCERT example.
Asked

Which one is not a marsupial.

Concept to use

Australian marsupials are the textbook case of adaptive radiation: one ancestral pouched stock filling niches that placental mammals occupy elsewhere. Numbat, koala and wombat are all Australian marsupials. The lemur is a primate from Madagascar — a placental mammal, and part of a different radiation entirely.

Diagram
AUSTRALIAmarsupial radiationnumbat — eats termiteskoala — eats eucalyptuswombat — burrowsMADAGASCARa different radiationlemura PRIMATEplacental, no pouchIn this chapter, “which is not a marsupial” almost alwaysmeans “which one is not Australian” — a far easier question.
AnimatedSort by continent and the odd one out picks itself.
Formula to useAustralia → marsupial radiation Madagascar → lemur (placental primate)
Baby steps
  1. Numbat — an Australian termite-eating marsupial.
  2. Koala — an Australian marsupial that feeds on eucalyptus.
  3. Wombat — an Australian burrowing marsupial.
  4. Lemur — a primate from Madagascar, placental, not pouched. This is the odd one out.
Answer
Lemur
Why this option and not the others
OptionVerdictReason
Numbatrule outA marsupial, and one of the standard examples in the Australian radiation.
Koalarule outA marsupial. It carries its young in a pouch like the rest.
Wombatrule outA marsupial, the burrowing member of the same radiation.
LemurkeepA placental primate from Madagascar. It belongs to a different continent, a different order and a different radiation.
Shortcut
Sort by continent. Numbat, wombat, koala, kangaroo, bandicoot, Tasmanian wolf and the marsupial mole are all Australian. A lemur is Madagascan. In this chapter, “which is not a marsupial” almost always means “which one is not Australian”, and that is a much easier question.
Where it went wrong
The koala is the most famous animal on the list, and in a not question familiarity is a trap rather than a help — the eye is drawn to the item it recognises. Two habits guard against this. First, underline the word “not” so the task is clear. Second, in an odd-one-out question, check the items you are keeping rather than the one you are picking: three Australian marsupials and one Madagascan primate makes the answer obvious.
Q 83Attempted · wrongFirst cellular life

The first cellular forms of life appeared about

  1. Correct2000 million years ago
  2. 200 million years ago
  3. Her answer4.5 million years ago
  4. 3 million years ago
Given
  • Standard dates from the Evolution chapter.
Asked

When the first cellular forms of life appeared.

Concept to use

The chapter gives the appearance of the first cells as about 2000 million years ago. Watch the units carefully — this figure is quoted in millions while the age of the earth and the universe are quoted in billions, and the distractors here exploit that switch.

Diagram
13.8 byauniverse forms4.5 byaearth forms2000 myafirst cellular life65 myadinosaurs die outThe four dates the chapter keeps asking foroldertodayCareful: NCERT still prints “almost 20 billion years” for the universe,while the modern astrophysical figure is 13.8 billion. Papers differ.
AnimatedThe same ladder, with the unit switch that builds the distractors.
Formula to useearth forms 4.5 billion → first cells 2000 million = 2 billion
Baby steps
  1. The earth itself formed about 4.5 billion years ago.
  2. The first cellular forms of life appeared about 2000 million years ago — that is 2 billion, so roughly halfway through the earth's history.
  3. Check the other options against the ladder: 200 million is around the age of the dinosaurs, and 3 to 4.5 million years is the range for early hominids.
  4. Only 2000 million fits.
Answer
2000 million years ago
Why this option and not the others
OptionVerdictReason
2000 millionkeepThe figure the chapter gives — about 2 billion years ago, well after the earth formed.
200 millionrule outRoughly the Jurassic. Life was already abundant and complex by then.
4.5 millionrule outThe right digits attached to the wrong unit. 4.5 billion is the age of the earth; 4.5 million is around the time of the earliest hominids.
3 millionrule outEarly hominid territory again. Far too recent for the first cells by a factor of about seven hundred.
Shortcut
The distractors in this cluster are built by keeping the digits and switching the unit — 4.5 billion becomes 4.5 million, and so on. So read the unit first and the number second. And use one anchor: cells cannot predate the earth, so any answer older than 4.5 billion is impossible, and any answer this recent needs checking against when the dinosaurs lived.
Where it went wrong
4.5 million keeps the digits of the earth's age and changes the unit, which is exactly how this distractor is built. A quick sanity check catches it: dinosaurs died out 65 million years ago, so if the first cells appeared 4.5 million years ago, cells would postdate the dinosaurs by 60 million years. Cross-checking a date against one other date on the ladder takes five seconds and rules out three of these four options.
Q 89Left blankPasteur and Miller · two statements

Given below are two statements.
Statement I: Pasteur's experiment put an end to theory of spontaneous generation.
Statement II: Miller's experiment supported the theory of chemical evolution.
In light of the above statements, choose the correct answer from the options given below.

  1. CorrectBoth statement I and statement II are correct.
  2. Both statement I and statement II are incorrect.
  3. Statement I is correct but statement II is incorrect.
  4. Statement I is incorrect but statement II is correct.
Given
  • Statement I concerns Louis Pasteur's swan-necked flask experiment.
  • Statement II concerns Stanley Miller's 1953 spark-chamber experiment.
Asked

Which of the two statements are correct.

Concept to use

The two experiments answer different questions, and both statements describe their own experiment accurately. Pasteur showed that killed yeast in a sealed flask never generated new life, while an open flask did — disproving spontaneous generation, the idea that life arises ready-made from non-living matter. Miller showed that simple inorganic gases, given energy, produce organic molecules — supporting chemical evolution, the idea that life's building blocks formed gradually from chemicals.

Diagram
Miller and Urey, 1953CH₄ H₂NH₃ H₂O800 °C sparkspark chamber = the early atmospherecondensedand trappedamino acids formedThe gases were the REDUCING atmosphere of the early earth — methane,hydrogen, ammonia and water vapour. There was no free oxygen, andno CO₂ in Miller's chamber.
AnimatedMiller's experiment, the subject of Statement II.
Formula to usePasteur → no spontaneous generation Miller → chemical evolution supported
Baby steps
  1. Statement I. Pasteur's swan-necked flasks admitted air but trapped dust and microbes. Nothing grew until the neck was broken. Spontaneous generation was finished. Correct.
  2. Statement II. Miller's chamber, holding CH₄, NH₃, H₂ and water vapour with electric discharges, produced amino acids. That is direct support for chemical evolution. Correct.
  3. Both statements stand, so the answer is that both are correct.
  4. Note the two are not in conflict: Pasteur ruled out life appearing ready-formed; Miller supported life's chemicals arising gradually. Different claims entirely.
Answer
Both statement I and statement II are correct
Why this option and not the others
OptionVerdictReason
Both correctkeepEach statement accurately describes what its experiment established.
Both incorrectrule outNeither statement contains an error — both are standard textbook conclusions.
I correct, II incorrectrule outStatement II is a fair description of Miller's result; amino acids formed from inorganic gases is precisely what chemical evolution predicts.
I incorrect, II correctrule outStatement I is the standard account of Pasteur's contribution and is not in dispute.
Shortcut
Statement-pair questions are worth attempting even when time is short, because there is no calculation and the odds are good. Read each statement on its own and ask only whether it is true, without trying to connect the two — here they concern different experiments and different claims, so looking for a link only creates doubt where there is none. Leaving these blank costs four marks for a question that needs about twenty seconds.

What the eighteen have in common

Reading the paper as a whole

Sixteen wrong answers, five underlying causes

CauseQuestionsMarksWhat is actually confused
Homologous vs analogous53, 55, 8115 Same job is being read as same origin. One question — do they share an ancestor, or just a job? — answers all three.
Incomplete vs co-dominance8, 3110 A blend is incomplete dominance; both traits appearing separately is co-dominance. The two were swapped in both questions.
Which cross, which generation1, 2, 2215 F₁ answered as F₂, Aa×aa answered as Aa×Aa. The genetics is sound; the setup is being read too fast.
Dates and names58, 74, 8315 Pure recall with no reasoning available. Q58 is a special case — see below.
Reading past the deciding word3, 46, 51, 78, 8225 “domestic”, “not”, “reducing”, “original ancestor” — each sitting in the stem and each decisive.

Three distinctions and one reading habit account for every wrong answer on the paper.

The one that is not really an error

Q58, the age of the universe. The answer given was 20 billion years, which is exactly what NCERT Class XII prints. The paper marked 13.8 billion correct, which is the modern astrophysical figure.

Answering from the prescribed textbook is normally the right instinct for NEET, so this is not a reasoning failure. The practical advice is to carry both numbers and know which source each belongs to: if an option list offers 13.8 and not 20, take 13.8; if it offers both, the paper is deliberately testing this, and 13.8 is the safer modern choice.

The single highest-value fix

Three questions — Q53, Q55 and Q81 — are the same question wearing different clothes, and all three were answered “homologous”. Together they are worth 15 marks.

The test is one sentence: homologous means same ancestor and different jobs; analogous means different ancestors and the same job. And a fast proxy: homologous pairs usually sit inside one group (vertebrate and vertebrate), analogous pairs cross groups (bird and insect, seal and penguin, squid and mammal).

The labels also travel in locked pairs — analogous always with convergent, homologous always with divergent. In Q81 that alone eliminates half the options before the animals are even considered.

Two habits to carry into the next paper