Every biology question flagged on this paper, rebuilt in full. Each one carries what was given, what was asked, the concept behind it, the rule, the steps written out, a table justifying the right option and ruling out each of the others, the fastest route through, and an animated figure wherever seeing the thing settles the answer.
18Questions lost
16Attempted, wrong
2Left blank
80Marks at stake
The shape of this paper
Eighteen questions, and the split is stark: sixteen attempted and missed against only two
left blank. That is an attempt rate of 89 per cent, far above anything in the earlier papers,
and it is genuine progress — the reluctance to commit has largely gone.
What it exposes instead is accuracy. On NEET marking the sixteen wrong answers cost 64 marks
in unearned scores plus 16 in negatives; the two blanks cost 8. The problem is no longer
whether to answer, it is which answer.
And the sixteen are not sixteen separate gaps. They collapse into about five recurring
confusions, which is a much smaller thing to fix than the raw number suggests.
Contents
Principles of Inheritance and Variation7 questions · 6 wrong · 1 blank Q1Q2Q3Q8Q22Q27Q31
Seven questions, six of them attempted and missed. Two of the six turn on the same confusion between incomplete dominance and co-dominance; two more turn on which generation or which cross the question is actually describing.
Q 1Attempted · wrongIncomplete dominance · back-working a cross
In Snapdragon, a cross produces pink and white flowers in a 1:1 ratio. This result is obtained by crossing plants with which flower colours?
In incomplete dominance every genotype has its own visible colour, so reading the offspring backwards is straightforward: pink offspring must be Rr and white offspring must be rr. A 1 : 1 ratio with only two classes is the signature of a test-cross pattern — one heterozygous parent crossed with one homozygote.
DiagramAnimatedThree dominance patterns, and what the heterozygote looks like in each.
Formula to useRr × rr → Rr : rr = 1 : 1 = pink : white
Baby steps
No red offspring appear at all, so no RR is ever produced — which means at least one parent cannot supply a second R.
White offspring (rr) appear, so both parents must be able to give an r.
Pink offspring (Rr) appear, so one parent must be able to give an R.
The only pair satisfying all three is Rr × rr — pink × white.
Rr × Rr gives 1 RR : 2 Rr : 1 rr = 1 red : 2 pink : 1 white. Red appears, and the ratio is 1:2:1, not 1:1.
Red × white
rule out
RR × rr gives every offspring as Rr — all pink, no white at all. This is the F₁ cross, not the one described.
Pink × white
keep
Rr × rr gives exactly 1 pink : 1 white, with no red. Matches the data on every point.
Red × pink
rule out
RR × Rr gives 1 RR : 1 Rr = 1 red : 1 pink. The ratio is right but the colours are wrong — no white is produced.
Shortcut
Two rules crack every backward cross of this kind. A 1 : 1 ratio always means heterozygote × homozygote. And whichever phenotypes are missing from the offspring tell you what the parents could not supply. Here red is missing, so no parent could give a second R — which rules out three of the four options immediately.
Where it went wrong
Red × white gives all-pink offspring, which is the classic F₁ result and probably the cross that came to mind first. But it produces no white at all, so it cannot give 1 : 1. The habit that catches this is to test the chosen option forwards before moving on — a single Punnett square, ten seconds, and the mismatch is obvious.
Q 2Attempted · wrongTest cross · probability
When crossing an organism that is a heterozygote with a homozygous recessive for a single trait, what is the chance of producing an offspring with the homozygous recessive phenotype?
0%
Her answer25%
Correct50%
75%
Given
Parent 1 is heterozygous: Aa.
Parent 2 is homozygous recessive: aa.
A single trait, ordinary complete dominance.
Asked
The chance of an offspring with the homozygous recessive phenotype.
Concept to use
This is a test cross, and it behaves quite differently from the carrier × carrier cross. The recessive parent can only ever give an a, so every offspring already has one a guaranteed. The whole outcome then rests on the single gamete from the heterozygous parent: A gives Aa, a gives aa — a straight coin toss.
DiagramAnimatedThe test cross Aa × aa: only one parent varies, so the split is 1 : 1.
Formula to useAa × aa → Aa : aa = 1 : 1 → 50% recessive
Baby steps
Heterozygote Aa makes two kinds of gamete in equal numbers: A and a.
Homozygous recessive aa makes only one kind: a.
Combining: A × a gives Aa, and a × a gives aa.
So the offspring are 1 Aa : 1 aa.
Recessive phenotype = aa = 1 in 2 = 50%.
Answer
50%
Why this option and not the others
Option
Verdict
Reason
0%
rule out
The heterozygote can supply a recessive allele, and the other parent always does, so aa offspring certainly occur.
25%
rule out
25% is the answer for Aa × Aa — two heterozygotes. Here the second parent is aa, which changes everything.
50%
keep
Only one parent varies, so the outcome is a straight 1 : 1 split.
75%
rule out
75% is the fraction showing the dominant phenotype in an Aa × Aa cross. Wrong cross and wrong phenotype.
Shortcut
When one parent is homozygous, that parent contributes nothing to the variation — it always sends the same allele. So count only the gametes of the other parent. A heterozygote makes two kinds equally, so the answer is 50%. This is why the test cross works as a tool: the ratio in the offspring is a direct readout of the unknown parent's gametes.
Where it went wrong
25% is the answer to the other standard cross, Aa × Aa, which appeared on the previous ILTS paper as the phenylketonuria question and was correct there. The two crosses look almost identical on the page and give different answers, so the distinguishing step has to be deliberate: read the second parent first. If it is homozygous, the answer is 50% or 0%; if it is heterozygous, it is 25% or 75%.
Q 3Attempted · wrongLaw of segregation
In the principles of inheritance, law of segregation is based on the fact that
CorrectThe alleles do not show any blending and the alleles/traits are recovered in the next generation.
The alleles of a trait always remain together, but only one of them can express its character.
The alleles of a trait never come together and they express their characters separately.
Her answerAll alleles of a trait lie on the same chromosome and they segregate during crossing over.
Given
Mendel's law of segregation.
Four candidate statements of what the law rests on.
Asked
The fact on which the law of segregation is based.
Concept to use
Segregation says that the two alleles of a gene sit together in a diploid organism but separate cleanly during gamete formation, so each gamete gets one and only one. The observational fact that forces this conclusion is what happens in F₂: the recessive trait, invisible throughout F₁, reappears unchanged. It was never diluted or blended — it was simply hidden and then recovered.
DiagramAnimatedF₂ of a monohybrid cross: the recessive is recovered unchanged.
Formula to useAa → gametes A and a, never Aa → recessive reappears intact in F₂
Baby steps
In F₁ the hybrid Aa looks entirely like the dominant parent, so a blending theory would predict the recessive character is lost or diluted.
In F₂ the recessive character comes back looking exactly as it did in the original parent — not faded, not intermediate.
That can only happen if the two alleles stayed separate and unaltered while together, then parted during gamete formation.
So the law rests on no blending, and recovery in the next generation.
Answer
The alleles do not show any blending and the alleles/traits are recovered in the next generation
Why this option and not the others
Option
Verdict
Reason
no blending, recovered later
keep
This is exactly what F₂ demonstrates, and it is the observation that killed the blending theory of inheritance.
always remain together, one expresses
rule out
The first half is wrong: alleles separate during gamete formation — that is the whole point of segregation. The second half describes dominance, a different law.
never come together
rule out
Also wrong: in a diploid the two alleles most certainly are together. They separate only when gametes form.
same chromosome, segregate at crossing over
rule out
Two errors. The two alleles of one gene lie on homologous chromosomes, not the same one. And they separate at anaphase I of meiosis, not through crossing over.
Shortcut
Each of Mendel's laws has one signature word. Dominance is about which allele shows. Segregation is about alleles separating into gametes. Independent assortment is about two different genes behaving independently. Match the option to the signature word and three of the four usually fall away.
Where it went wrong
The chosen option puts both alleles of one gene on the same chromosome, and then makes crossing over do the separating. Both halves are wrong, and they are wrong in a related way: alleles of a single gene occupy the same locus on the two homologous chromosomes, so they are pulled apart when the homologues separate at anaphase I. Crossing over exchanges segments between homologues and is the mechanism behind recombination, not segregation. Worth noting that this is a mechanism question dressed as a definition question — and the mechanism is the part that slipped.
If size of starch grains in pea is considered as phenotype, Bb alleles show
Her answerco-dominance
dominance
Correctincomplete dominance
pleiotropism
Given
Pea seed starch grains, gene B.
BB produces large starch grains, bb produces small ones.
The heterozygote is Bb.
Asked
What kind of dominance Bb shows when starch grain size is the phenotype.
Concept to use
The same gene can show different dominance relationships depending on which phenotype you look at. Judged by seed shape, Bb peas are round like BB — complete dominance. But judged by starch grain size, Bb grains are intermediate: bigger than bb, smaller than BB. An intermediate heterozygote is the definition of incomplete dominance.
DiagramAnimatedA blend is incomplete dominance; both traits together is co-dominance.
Formula to useBB (large) > Bb (INTERMEDIATE) > bb (small) → incomplete dominance
Baby steps
BB seeds have large starch grains; bb seeds have small ones.
Bb seeds have grains of intermediate size — a blend, not a copy of either parent.
A heterozygote showing a blend is incomplete dominance.
Note the contrast: for seed shape, Bb is fully round like BB, so the same gene shows complete dominance on that phenotype. Dominance is a property of the phenotype you choose to measure, not of the gene alone.
Answer
Incomplete dominance
Why this option and not the others
Option
Verdict
Reason
co-dominance
rule out
Co-dominance means both parental phenotypes appear separately and fully in the same individual — like the AB blood group, where both A and B antigens are present. Intermediate-sized grains are a blend, not two distinct types side by side.
dominance
rule out
This is true for seed shape but not for grain size. The stem specifies size.
incomplete dominance
keep
The heterozygote is intermediate between the two homozygotes — the textbook definition.
pleiotropism
rule out
Pleiotropy is one gene affecting several unrelated traits. It is genuinely relevant to this gene — B affects both shape and starch — but it is not what the question asks about the Bb relationship.
Shortcut
The distinction between the two tempting options comes down to a single question: is the heterozygote a mixture, or a mosaic? A mixture — pink between red and white, medium between large and small — is incomplete dominance. A mosaic, both parental types visible separately and unchanged, is co-dominance. Blends blend; co-dominants coexist.
Where it went wrong
Co-dominance and incomplete dominance are the pair this chapter tests most often, and the line between them is exactly the blend-versus-both distinction. An intermediate grain size is one new value in between, not two original values appearing together, so it is a blend. Note that this same pair reappears as Q31 on this paper, where options I and III had to be told apart on the same grounds — and the same two were swapped there. That makes it one confusion costing two questions.
Q 22Attempted · wrongTrue-breeding cross · the F₁ generation
A true breeding violet-flowered garden pea plant is crossed with a white-flowered garden pea plant. What is the expected ratio of violet and white-flowered plants in the offspring?
Correct1 violet flowered : 0 white flowered
Her answer3 violet flowered : 1 white flowered
0 violet flowered : 1 white flowered
1 violet flowered : 1 white flowered
Given
A true-breeding violet-flowered pea: VV.
A white-flowered pea: vv (white is recessive, so white plants are always homozygous).
Violet is completely dominant over white.
Asked
The ratio of violet to white in the offspring of this cross.
Concept to use
Two words decide this. True-breeding means homozygous, so the violet parent is VV, not Vv. And offspring means the immediate next generation, F₁ — not F₂. A VV × vv cross can only produce Vv, and every Vv plant is violet.
DiagramAnimatedVV × vv: the F₁ generation is completely uniform.
Formula to useVV × vv → all Vv → 100% violet = 1 : 0
Baby steps
True-breeding violet gives only V gametes.
White is recessive, so a white plant must be vv and gives only v gametes.
Every offspring is therefore Vv.
Vv is violet, since violet is completely dominant.
All offspring are violet: the ratio is 1 : 0.
Answer
1 violet : 0 white
Why this option and not the others
Option
Verdict
Reason
1 : 0
keep
Every F₁ plant is Vv and therefore violet. No white appears in this generation at all.
3 : 1
rule out
This is the F₂ ratio, obtained by selfing the F₁. The question stops one generation earlier.
0 : 1
rule out
This would need the violet parent to contribute no V, which contradicts true-breeding violet.
1 : 1
rule out
This is the test-cross ratio, Vv × vv. It would apply if the violet parent were heterozygous — but true-breeding rules that out.
Shortcut
Count the generations in the stem. One cross described means F₁, and F₁ from two true-breeding parents is always uniform — 100% of the dominant type, ratio 1 : 0. The famous 3 : 1 needs a second step, the selfing of F₁, and the question has to say so. If you see only one cross, 3 : 1 is not available.
Where it went wrong
3 : 1 is the most famous ratio in the chapter, and it is the F₂ ratio. The question describes a single cross, which produces F₁ only. This is a generation-counting error rather than a genetics error — the underlying understanding of dominance is intact, and the fix is to circle the word “offspring” and ask of which cross? before reaching for a remembered ratio.
Q 27Left blankF₂ · counting TYPES, not individuals
In a pea plant, Mendel obtained the ratio between the types of phenotypes and genotypes in F₂ generation of monohybrid cross is
Correct2:3
1 : 2 : 1
3:1
1:1
Given
A monohybrid cross, F₂ generation.
Phenotypic ratio in F₂ = 3 : 1.
Genotypic ratio in F₂ = 1 : 2 : 1.
Asked
The ratio between the number of types of phenotypes and the number of types of genotypes.
Concept to use
This question is not asking for either of the two famous ratios — it is asking how many different kinds there are of each. In F₂ of a monohybrid cross there are two phenotypes (tall and dwarf) and three genotypes (TT, Tt, tt). So the answer is a count of categories, 2 : 3, not a count of individuals.
DiagramAnimatedCount the distinct kinds in each row, not the number of individuals.
Formula to usephenotype TYPES = 2 (3 : 1) genotype TYPES = 3 (1 : 2 : 1) ratio = 2 : 3
Baby steps
Write out the F₂ genotypes: TT, Tt, Tt, tt.
How many different genotypes? TT, Tt, tt — that is 3 types.
How many different phenotypes? Tall and dwarf — that is 2 types.
The stem asks for phenotypes : genotypes, in that order.
Ratio = 2 : 3.
Answer
2 : 3
Why this option and not the others
Option
Verdict
Reason
2:3
keep
Two kinds of phenotype against three kinds of genotype. This is a count of categories, which is what “the types of” means.
1 : 2 : 1
rule out
The genotypic ratio itself — the numbers of individuals, not the number of kinds.
3:1
rule out
The phenotypic ratio itself. Again individuals, not kinds.
1:1
rule out
Neither a Mendelian ratio for F₂ nor a count of types.
Shortcut
The tell is the phrase “the ratio between the types of”. Whenever a stem says types, kinds or classes, stop and count categories rather than reaching for a remembered ratio. Two of the four options here are simply the two famous ratios, offered precisely because they are what the eye jumps to.
Q 31Attempted · wrongMatch · dominance patterns and Mendel's laws
Match the following genetic concepts (List I) with their features/examples (List II). A. Complete Dominance I. F₁ shows an intermediate phenotype B. Incomplete Dominance II. Each allele separates during gamete formation C. Co-dominance III. F₁ shows both parental traits D. Law of Segregation IV. F₁ shows only the dominant trait
CorrectA – IV, B – I, C – III, D – II
A – III, B – IV, C – I, D – II
A – I, B – II, C – III, D – IV
Her answerA – IV, B – III, C – I, D – II
Given
Four concepts: complete dominance, incomplete dominance, co-dominance, law of segregation.
Four features describing what F₁ looks like, plus one about gamete formation.
Asked
The correct matching.
Concept to use
Three of the four are about what the heterozygote looks like, and they form a clean progression. Complete dominance: F₁ looks like one parent only. Incomplete dominance: F₁ looks like a blend of the two. Co-dominance: F₁ shows both parental traits, fully and separately. The fourth, segregation, is the odd one out — it is about gametes, not appearance, and it pairs with the only option mentioning gametes.
DiagramAnimatedThe three dominance patterns side by side, which is what List II describes.
Formula to useone parent → complete · a blend → incomplete · both → co-dominance
Baby steps
D first, because it is the easiest. Law of segregation is the only concept about gametes, and II is the only feature about gametes. D – II.
A. Complete dominance — the heterozygote shows only the dominant trait. A – IV.
B. Incomplete dominance — the heterozygote is intermediate, a blend. B – I.
C. Co-dominance — the heterozygote shows both parental traits at once. C – III.
Answer: A – IV, B – I, C – III, D – II.
Answer
A – IV, B – I, C – III, D – II
Why this option and not the others
Option
Verdict
Reason
A-IV, B-I, C-III, D-II
keep
Each concept sits with its own definition; the blend goes to incomplete and both-traits goes to co-dominance.
A-III, B-IV, C-I, D-II
rule out
Puts “both parental traits” on complete dominance, which is the opposite of what complete dominance means.
A-I, B-II, C-III, D-IV
rule out
Matches segregation to “only the dominant trait”, which is a dominance statement, not a segregation one.
A-IV, B-III, C-I, D-II
rule out
A and D are right, but B and C are swapped: intermediate belongs to incomplete dominance and both-traits to co-dominance.
Shortcut
In any matching question, do the odd one out first. Here three items are about appearance and one is about gametes, so D – II is free and instantly narrows the field. Then remember the one-word test for the remaining pair: intermediate is incomplete, both is co-dominance.
Where it went wrong
A and D were placed correctly, so the structure of the question was understood. B and C were swapped — incomplete dominance was given “both parental traits” and co-dominance was given “intermediate”. This is the same confusion as Q8 on this paper, where co-dominance was chosen for an intermediate starch grain size. One mixed-up pair cost two questions and 10 marks. Fixing that single distinction is the highest-value thing in this chapter.
Evolution
10 wrong · 1 blank
Eleven questions, ten of them attempted and missed. Three of the ten are the same homologous-versus-analogous distinction asked three different ways, and three more are pure recall — dates and names, with no reasoning available.
Q 46Attempted · wrongMiller's experiment · the gases
Which of the following gases were used in the spark chamber of Miller's simulation experiment?
Her answerCH₄, H₂, NH₃, CO₂
CorrectCH₄, H₂O, NH₃, H₂
H₂, O₂, CH₄, NH₃
H₂O, C₂H₅OH, NH₃
Given
Stanley Miller's 1953 simulation of the early earth.
The chamber was meant to reproduce the primitive reducing atmosphere.
Asked
Which gases were placed in the spark chamber.
Concept to use
Miller was trying to recreate an atmosphere with no free oxygen — a reducing one, in which hydrogen is abundant. The four things he sealed in were methane, ammonia, hydrogen and water vapour, with electric discharges at 800 °C standing in for lightning. After a week the condensed liquid contained amino acids.
DiagramAnimatedThe spark chamber and the four gases sealed inside it.
Formula to useCH₄ + NH₃ + H₂ + H₂O + spark → amino acids
Baby steps
The early atmosphere had no free oxygen — that rules out any option containing O₂ at once.
It was reducing, i.e. rich in hydrogen, so H₂ must be present.
The carbon came in as methane, not as carbon dioxide, since CO₂ is an oxidised form of carbon.
Water vapour supplied the oxygen and hydrogen for the amino acids.
So the set is CH₄, H₂O, NH₃, H₂.
Answer
CH₄, H₂O, NH₃, H₂
Why this option and not the others
Option
Verdict
Reason
CH₄, H₂, NH₃, CO₂
rule out
CO₂ is oxidised carbon and does not belong in a reducing atmosphere; and water vapour, which was definitely present, is missing.
CH₄, H₂O, NH₃, H₂
keep
The four gases Miller actually used — all reduced forms, no free oxygen.
H₂, O₂, CH₄, NH₃
rule out
Contains free O₂, which is exactly what the early atmosphere lacked. Oxygen would have destroyed the organic molecules as they formed.
H₂O, C₂H₅OH, NH₃
rule out
Ethanol is already an organic molecule. Putting it in would defeat the purpose of the experiment, which was to make organics from inorganics.
Shortcut
One word carries the whole question: reducing. That means hydrogen-rich and oxygen-free, so cross out anything with O₂ and anything with carbon in an oxidised form like CO₂. Two options die on that test alone, and a third dies because ethanol is organic. The four gases are worth memorising as a single unit — methane, ammonia, hydrogen, water vapour.
Where it went wrong
The chosen option swaps water vapour for CO₂. It keeps three of the four right, so the general picture was correct, but CO₂ is an oxidised carbon compound and its presence contradicts the reducing atmosphere the experiment was designed around. Water vapour, meanwhile, is not optional — it is what condenses and carries the amino acids into the trap.
Q 51Attempted · wrongArtificial selection
Most modern breeds of domestic dog have evolved by
Her answernatural selection
Correctartificial selection
sexual selection
temporal isolation
Given
Modern breeds of domestic dog.
They descend from wolf ancestors over a few thousand years.
Asked
The process by which they arose.
Concept to use
The question turns on who did the choosing. In natural selection the environment decides which individuals survive and reproduce. In artificial selection humans decide — picking the animals with the traits they want and breeding from those. Every dog breed exists because people chose the parents, generation after generation.
DiagramAnimatedWho did the choosing — the environment, or a person?
Formula to useenvironment chooses → NATURAL humans choose → ARTIFICIAL
Baby steps
Ask what would happen to a chihuahua or a dachshund in the wild. Neither would be favoured by any natural pressure.
These forms exist because breeders selected them deliberately for size, coat, temperament or working ability.
Human-directed selection is artificial selection.
Darwin used exactly this — domestic pigeons and dogs — as his everyday illustration of how selection works, before arguing that nature does the same thing unaided.
Answer
Artificial selection
Why this option and not the others
Option
Verdict
Reason
natural selection
rule out
The environment did not favour these forms; humans did. In the wild most breeds would fare badly.
artificial selection
keep
Humans chose which dogs bred, generation after generation. This is the textbook example, along with cabbage, broccoli and kale from wild mustard.
sexual selection
rule out
Sexual selection is mate choice by the animals themselves — peacock tails, stag antlers. Domestic dogs are generally not choosing their own mates.
temporal isolation
rule out
This is a mechanism of speciation — two populations breeding at different times of year. It is not a selection process at all.
Shortcut
Whenever a question names something domesticated — dogs, cattle, crop plants, pigeons — the answer is artificial selection. The word “domestic” in the stem is doing the work.
Where it went wrong
Natural and artificial selection use the same mechanism, so choosing the wrong one is understandable — but the distinguishing question is a single one: did a human make the choice? Here the stem says “domestic”, which answers it directly. This is the second question on this paper (with Q22) where the deciding word was present in the stem and was read past.
Q 53Attempted · wrongHomologous organs
Which of the following are considered homologous organs?
CorrectVertebrate hearts and brains
Eyes of squids and of mammals
Limbs of arthropods and frogs
Her answerVertebrate hearts and insect hearts
Given
Four pairs of organs from different animals.
Asked
Which pair is homologous.
Concept to use
Homologous organs share the same basic structural plan inherited from a common ancestor, even if they now do different jobs. Analogous organs are the reverse: different structural plans that arrived at the same job because of similar pressures. The quick test is whether the two animals belong to the same major group. Homology usually sits inside a group; analogy usually crosses between groups.
DiagramAnimatedShared ancestor, or shared job? The one question that decides both.
Formula to usesame ancestor, structure shared → HOMOLOGOUS (divergent)
Baby steps
All vertebrates — fish, amphibians, reptiles, birds, mammals — share a common ancestor.
Their hearts follow one basic plan, modified from two chambers to four; their brains likewise share fore-, mid- and hindbrain divisions.
So vertebrate hearts (across vertebrates) and vertebrate brains are both homologous sets — same plan, common ancestry, varying detail.
The other three pairs each cross between unrelated groups, which makes them analogous.
Answer
Vertebrate hearts and brains
Why this option and not the others
Option
Verdict
Reason
Vertebrate hearts and brains
keep
Both are structures shared across the vertebrates by descent from a common ancestor, varying in form but built on one plan.
Eyes of squids and of mammals
rule out
The classic analogy: a mollusc eye and a vertebrate eye do the same job with quite different construction and separate evolutionary origins.
Limbs of arthropods and frogs
rule out
An arthropod limb has an external skeleton and a frog limb an internal one — different plans, no shared limb ancestry. Analogous.
Vertebrate hearts and insect hearts
rule out
An insect heart is a simple dorsal tube pumping haemolymph in an open system. It shares no structural plan with a vertebrate heart. Analogous.
Shortcut
Run one test on the pair: do these two animals belong to the same major group? Vertebrate-and-vertebrate is a homology candidate. Squid-and-mammal, arthropod-and-frog, insect-and-vertebrate all cross between phyla and are therefore analogies. Three of the four options here fail on that single check.
Where it went wrong
Insect hearts and vertebrate hearts do the same job, and same-job is exactly the definition of analogous, not homologous. The two words were applied the wrong way round. Note that Q55 and Q81 on this same paper turn on the identical distinction and were also answered with “homologous” — three questions, twelve marks, one definition.
Q 55Attempted · wrongAnalogous organs
Flippers of seals and penguins are an example of
Her answerhomologous organs
Correctanalogous organs
atavistic organs
vestigial organs
Given
A seal is a mammal; a penguin is a bird.
Both have flipper-shaped limbs used for swimming.
Asked
What kind of organs these flippers are.
Concept to use
Both animals swim, and water imposes the same demands whatever your ancestry: a flat, paddle-like limb. A seal's flipper is a modified mammalian forelimb; a penguin's is a modified bird wing. Two different starting structures pushed into the same shape by the same environment is convergent evolution, and the resulting organs are analogous.
DiagramAnimatedSeal and penguin sit in different classes, so the flippers are analogous.
Formula to usedifferent ancestry + same job → ANALOGOUS (convergent)
Baby steps
Identify the groups: seal = mammal, penguin = bird. Different classes.
Identify the job: both flippers are for swimming. Same function.
Different origin plus same function = analogous.
The underlying cause is convergent evolution — similar environments producing similar solutions independently.
Answer
Analogous organs
Why this option and not the others
Option
Verdict
Reason
homologous organs
rule out
Homology would require a shared flipper-bearing ancestor. The last common ancestor of birds and mammals had no flippers at all.
analogous organs
keep
Same function, different structural origin, arrived at independently — the definition of analogy.
atavistic organs
rule out
An atavism is the reappearance of an ancestral feature that had been lost — a human born with a tail. Flippers are not reappearances.
vestigial organs
rule out
A vestigial organ is a reduced, functionless remnant — the human appendix, the vermiform coccyx. These flippers are fully functional and essential.
Shortcut
Note the trap built into the phrasing. A seal's flipper and a whale's flipper would be homologous, since both are mammals. Swapping the whale for a penguin changes the answer entirely. So read the two animals before reading the organ — the classes decide it, not the shape.
Where it went wrong
The flippers look alike, and that similarity is precisely what the question is testing. Looking alike is evidence of analogy when the animals are unrelated. The single question that resolves it — are these two animals in the same class? — would have given bird and mammal, and therefore analogous. This is the same slip as Q53 and Q81.
Q 58Attempted · wrongAge of the universe
Worth knowing the sources disagreeThis paper marks 13.8 billion years correct, which is the modern astrophysical figure. NCERT Class XII still prints “the universe is very old — almost 20 billion years old”, which is the option chosen. So the answer given was the NCERT answer, and it was marked wrong against a scientifically updated key. Carry both numbers and take the paper's cue.
The age of the universe is approximately
4.5 billion years
Correct13.8 billion years
Her answer20 billion years
65 million years
Given
Standard dates from the Evolution chapter.
Asked
The approximate age of the universe.
Concept to use
The chapter uses four landmark dates and they get shuffled between questions, so they are best learned as one set rather than one at a time: the universe forms, the earth forms, the first cellular life appears, and the dinosaurs die out. Only the first of these is asked here.
DiagramAnimatedThe four landmark dates, with the NCERT discrepancy noted.
Formula to useuniverse 13.8 bya · earth 4.5 bya · first cells 2000 mya · dinosaurs out 65 mya
Baby steps
The Big Bang is dated by the cosmic microwave background and the expansion rate.
The current accepted figure is 13.8 billion years.
4.5 billion is the age of the earth, not the universe — the commonest confusion in this set.
65 million years is when the dinosaurs disappeared, a vastly more recent event.
Answer
13.8 billion years (see the note above on NCERT's figure)
Why this option and not the others
Option
Verdict
Reason
4.5 billion
rule out
The age of the earth. Right number, wrong object — and it is the most frequently offered distractor in this question.
13.8 billion
keep
The modern astrophysical value, and the one this paper's key uses.
20 billion
rule out
Marked incorrect here, but it is the figure printed in NCERT. See the note at the top of this card — this is a genuine textbook-versus-science disagreement, not a mistake in reasoning.
65 million
rule out
The end of the Cretaceous and of the dinosaurs. Off by a factor of about two hundred.
Shortcut
Learn the four dates as one ladder, biggest to smallest, and most questions in this cluster become a lookup: 13.8 billion → 4.5 billion → 2000 million → 65 million. Note the unit switch halfway down — billions become millions — which is where the errors usually creep in.
Where it went wrong
This one is not really an error. The option chosen, 20 billion, is what NCERT states, and answering from the prescribed textbook is normally the right instinct for NEET. The paper has used the updated scientific value instead. The useful takeaway is to know both numbers and which source each belongs to: if an option list offers 13.8 and does not offer 20, take 13.8; if it offers both, the paper is deliberately testing this, and 13.8 is the safer modern choice.
Q 74Attempted · wrongEmbryological evidence
Embryological support for evolution was proposed by
Lamarck
Her answerCharles Darwin
Alfred Wallace
CorrectErnst Haeckel
Given
The embryological line of evidence for evolution.
Asked
Who proposed it.
Concept to use
Ernst Haeckel observed that vertebrate embryos of different species pass through similar stages, and proposed that an embryo repeats its evolutionary history as it develops — his “biogenetic law”. The classic example is the gill slits present in the embryos of all vertebrates, including humans. NCERT also notes that this was later disproved by Karl Ernst von Baer, who showed embryos never pass through the adult stages of other animals.
DiagramAnimatedMiller's apparatus — a reminder of which name goes with which experiment.
Formula to useHaeckel: embryology as evidence → von Baer: the recapitulation claim disproved
Baby steps
The claim is that embryonic development retraces evolutionary ancestry.
Its author is Ernst Haeckel.
The evidence cited is the set of features shared by early vertebrate embryos, such as gill slits.
NCERT then records that von Baer disproved the strong form of the claim — a detail that is itself examined, so keep both names attached to this topic.
Answer
Ernst Haeckel
Why this option and not the others
Option
Verdict
Reason
Lamarck
rule out
Lamarck is associated with the inheritance of acquired characters — the giraffe's neck — not with embryology.
Charles Darwin
rule out
Darwin proposed natural selection and gathered many lines of evidence, but the embryological argument is Haeckel's. Darwin is the default answer to any evolution question, which is exactly why he is offered here.
Alfred Wallace
rule out
Wallace arrived at natural selection independently and studied the Malay Archipelago. Not embryology.
Ernst Haeckel
keep
Author of the biogenetic law, and the name NCERT attaches to embryological support for evolution.
Shortcut
Attach one name to one idea and keep the pairs tight: Lamarck — acquired characters. Darwin and Wallace — natural selection. Haeckel — embryology. von Baer — the man who disproved Haeckel. Miller and Urey — chemical evolution. When Darwin appears as an option in a question about a specific line of evidence, be suspicious: he is the most attractive wrong answer in the whole chapter.
Where it went wrong
Darwin is the name most strongly associated with evolution, so he is the natural first reach — and papers exploit that. The specific attribution here is Haeckel's. Names in this chapter are pure recall with no reasoning available, which makes them worth a dedicated ten-minute memorisation pass rather than an attempt to work out in the exam hall.
Q 78Attempted · wrongDarwin's finches · the ancestral form
Which type of finch is considered the original ancestor of Darwin's finches?
Insect eater
Cactus eater
CorrectSeed eater
Her answerWoodpecker
Given
Darwin's finches of the Galapagos islands.
They now occupy many feeding niches: seeds, insects, cactus, and a tool-using woodpecker-like form.
Asked
Which type was the original ancestral form.
Concept to use
A small population of seed-eating ground finches reached the Galapagos from the mainland. With many empty niches and no competition, their descendants diversified into forms with quite different beaks — insect eaters, cactus feeders, a woodpecker-like finch. That process, one ancestral stock radiating into many forms in a new place, is adaptive radiation.
DiagramAnimatedOne seed-eating ancestor, radiating into many specialists.
Formula to useone seed-eating ancestor → many beak forms = ADAPTIVE RADIATION
Baby steps
The founding birds were ordinary mainland seed eaters.
On reaching the islands they found many unoccupied feeding niches.
Over generations, beak form diversified to exploit those niches.
The specialised forms — insect eater, cactus eater, woodpecker finch — are the results of the radiation, not its starting point.
Answer
Seed eater
Why this option and not the others
Option
Verdict
Reason
Insect eater
rule out
A derived form, produced by the radiation.
Cactus eater
rule out
Also derived — a specialist that could only arise once the birds were on the islands.
Seed eater
keep
The ancestral ground finch. Seed eating is the generalist starting condition from which the specialists diverged.
Woodpecker
rule out
The woodpecker finch is the most specialised of all — it uses a cactus spine as a tool. A highly specialised form is the least likely candidate for an ancestor.
Shortcut
In any adaptive radiation question, the ancestor is the generalist and the descendants are the specialists. So look down the option list for the least specialised item and pick it. The woodpecker finch, being the most specialised of the four, is the least likely ancestor on that principle alone — you can reason to the answer without recalling the fact.
Where it went wrong
The woodpecker finch is the most memorable of Darwin's finches because of the tool use, which is probably why it came to mind. But memorability and ancestry point in opposite directions here: the striking specialist is the end of a radiation, never its beginning. The general principle — radiations run from generalist to specialist — would have given the answer without needing the specific fact.
Q 81Attempted · wrongAnalogy and convergent evolution together
The wings of a bird and the wings of an insect are
homologous structures and represent convergent evolution
Her answerhomologous structures and represent divergent evolution
Correctanalogous structures and represent convergent evolution
phylogenetic structures and represent divergent evolution
Given
A bird wing: a modified vertebrate forelimb, with bones.
An insect wing: an outgrowth of the body wall, with no bones at all.
Both are used for flight.
Asked
What kind of structures they are, and which pattern of evolution they represent.
Concept to use
Two labels have to be got right and they always travel together. Analogous structures — different construction, same function — are the product of convergent evolution, where unrelated lineages are pushed towards the same solution. Homologous structures — same construction, different functions — are the product of divergent evolution, where one ancestral plan is modified in different directions.
DiagramAnimatedThe labels travel in pairs: analogous with convergent, homologous with divergent.
Formula to useanalogous → convergent homologous → divergent
Baby steps
Compare construction: a bird wing has humerus, radius, ulna and digits; an insect wing is a thin extension of the cuticle with no skeleton inside.
Completely different construction, so not homologous.
Same function, flight, arrived at independently: analogous.
Analogy is always the signature of convergent evolution.
A mismatched pair — homology never goes with convergence. The two labels are locked together.
homologous + divergent
rule out
The pairing is internally consistent, but the first label is wrong: birds and insects share no winged ancestor.
analogous + convergent
keep
Different construction, same job, independent origin — analogy, and therefore convergence.
phylogenetic + divergent
rule out
“Phylogenetic structures” is not a recognised category. An invented term in an option list is almost always a filler.
Shortcut
Because the two labels are locked together, half the options in any question of this shape are internally inconsistent and can be crossed out without looking at the animals at all. Here that removes the homologous-convergent pairing straight away. Then one glance at construction — bones or no bones — settles the rest.
Where it went wrong
Both labels were chosen wrongly, but consistently: homologous-with-divergent is a valid pairing, just not the right one for this animal pair. So the relationship between the two terms is understood; what failed is the same structure-versus-function test as in Q53 and Q55. Three questions on this paper, twelve marks, and one distinction to fix: do they share an ancestor, or just a job?
Q 82Attempted · wrongMarsupials · the odd one out
Which of the following is not a marsupial?
Numbat
Her answerKoala
Wombat
CorrectLemur
Given
Four mammals.
Marsupials are pouched mammals, and Australia's adaptive radiation of them is the standard NCERT example.
Asked
Which one is not a marsupial.
Concept to use
Australian marsupials are the textbook case of adaptive radiation: one ancestral pouched stock filling niches that placental mammals occupy elsewhere. Numbat, koala and wombat are all Australian marsupials. The lemur is a primate from Madagascar — a placental mammal, and part of a different radiation entirely.
DiagramAnimatedSort by continent and the odd one out picks itself.
Formula to useAustralia → marsupial radiation Madagascar → lemur (placental primate)
Baby steps
Numbat — an Australian termite-eating marsupial.
Koala — an Australian marsupial that feeds on eucalyptus.
Wombat — an Australian burrowing marsupial.
Lemur — a primate from Madagascar, placental, not pouched. This is the odd one out.
Answer
Lemur
Why this option and not the others
Option
Verdict
Reason
Numbat
rule out
A marsupial, and one of the standard examples in the Australian radiation.
Koala
rule out
A marsupial. It carries its young in a pouch like the rest.
Wombat
rule out
A marsupial, the burrowing member of the same radiation.
Lemur
keep
A placental primate from Madagascar. It belongs to a different continent, a different order and a different radiation.
Shortcut
Sort by continent. Numbat, wombat, koala, kangaroo, bandicoot, Tasmanian wolf and the marsupial mole are all Australian. A lemur is Madagascan. In this chapter, “which is not a marsupial” almost always means “which one is not Australian”, and that is a much easier question.
Where it went wrong
The koala is the most famous animal on the list, and in a not question familiarity is a trap rather than a help — the eye is drawn to the item it recognises. Two habits guard against this. First, underline the word “not” so the task is clear. Second, in an odd-one-out question, check the items you are keeping rather than the one you are picking: three Australian marsupials and one Madagascan primate makes the answer obvious.
Q 83Attempted · wrongFirst cellular life
The first cellular forms of life appeared about
Correct2000 million years ago
200 million years ago
Her answer4.5 million years ago
3 million years ago
Given
Standard dates from the Evolution chapter.
Asked
When the first cellular forms of life appeared.
Concept to use
The chapter gives the appearance of the first cells as about 2000 million years ago. Watch the units carefully — this figure is quoted in millions while the age of the earth and the universe are quoted in billions, and the distractors here exploit that switch.
DiagramAnimatedThe same ladder, with the unit switch that builds the distractors.
Formula to useearth forms 4.5 billion → first cells 2000 million = 2 billion
Baby steps
The earth itself formed about 4.5 billion years ago.
The first cellular forms of life appeared about 2000 million years ago — that is 2 billion, so roughly halfway through the earth's history.
Check the other options against the ladder: 200 million is around the age of the dinosaurs, and 3 to 4.5 million years is the range for early hominids.
Only 2000 million fits.
Answer
2000 million years ago
Why this option and not the others
Option
Verdict
Reason
2000 million
keep
The figure the chapter gives — about 2 billion years ago, well after the earth formed.
200 million
rule out
Roughly the Jurassic. Life was already abundant and complex by then.
4.5 million
rule out
The right digits attached to the wrong unit. 4.5 billion is the age of the earth; 4.5 million is around the time of the earliest hominids.
3 million
rule out
Early hominid territory again. Far too recent for the first cells by a factor of about seven hundred.
Shortcut
The distractors in this cluster are built by keeping the digits and switching the unit — 4.5 billion becomes 4.5 million, and so on. So read the unit first and the number second. And use one anchor: cells cannot predate the earth, so any answer older than 4.5 billion is impossible, and any answer this recent needs checking against when the dinosaurs lived.
Where it went wrong
4.5 million keeps the digits of the earth's age and changes the unit, which is exactly how this distractor is built. A quick sanity check catches it: dinosaurs died out 65 million years ago, so if the first cells appeared 4.5 million years ago, cells would postdate the dinosaurs by 60 million years. Cross-checking a date against one other date on the ladder takes five seconds and rules out three of these four options.
Q 89Left blankPasteur and Miller · two statements
Given below are two statements. Statement I: Pasteur's experiment put an end to theory of spontaneous generation. Statement II: Miller's experiment supported the theory of chemical evolution. In light of the above statements, choose the correct answer from the options given below.
CorrectBoth statement I and statement II are correct.
Both statement I and statement II are incorrect.
Statement I is correct but statement II is incorrect.
Statement I is incorrect but statement II is correct.
Given
Statement I concerns Louis Pasteur's swan-necked flask experiment.
Statement II concerns Stanley Miller's 1953 spark-chamber experiment.
Asked
Which of the two statements are correct.
Concept to use
The two experiments answer different questions, and both statements describe their own experiment accurately. Pasteur showed that killed yeast in a sealed flask never generated new life, while an open flask did — disproving spontaneous generation, the idea that life arises ready-made from non-living matter. Miller showed that simple inorganic gases, given energy, produce organic molecules — supporting chemical evolution, the idea that life's building blocks formed gradually from chemicals.
DiagramAnimatedMiller's experiment, the subject of Statement II.
Formula to usePasteur → no spontaneous generation Miller → chemical evolution supported
Baby steps
Statement I. Pasteur's swan-necked flasks admitted air but trapped dust and microbes. Nothing grew until the neck was broken. Spontaneous generation was finished. Correct.
Statement II. Miller's chamber, holding CH₄, NH₃, H₂ and water vapour with electric discharges, produced amino acids. That is direct support for chemical evolution. Correct.
Both statements stand, so the answer is that both are correct.
Note the two are not in conflict: Pasteur ruled out life appearing ready-formed; Miller supported life's chemicals arising gradually. Different claims entirely.
Answer
Both statement I and statement II are correct
Why this option and not the others
Option
Verdict
Reason
Both correct
keep
Each statement accurately describes what its experiment established.
Both incorrect
rule out
Neither statement contains an error — both are standard textbook conclusions.
I correct, II incorrect
rule out
Statement II is a fair description of Miller's result; amino acids formed from inorganic gases is precisely what chemical evolution predicts.
I incorrect, II correct
rule out
Statement I is the standard account of Pasteur's contribution and is not in dispute.
Shortcut
Statement-pair questions are worth attempting even when time is short, because there is no calculation and the odds are good. Read each statement on its own and ask only whether it is true, without trying to connect the two — here they concern different experiments and different claims, so looking for a link only creates doubt where there is none. Leaving these blank costs four marks for a question that needs about twenty seconds.
What the eighteen have in common
Reading the paper as a whole
Sixteen wrong answers, five underlying causes
Cause
Questions
Marks
What is actually confused
Homologous vs analogous
53, 55, 81
15
Same job is being read as same origin. One question — do they share an ancestor,
or just a job? — answers all three.
Incomplete vs co-dominance
8, 31
10
A blend is incomplete dominance; both traits appearing separately is co-dominance. The two
were swapped in both questions.
Which cross, which generation
1, 2, 22
15
F₁ answered as F₂, Aa×aa answered as Aa×Aa. The genetics is sound; the
setup is being read too fast.
Dates and names
58, 74, 83
15
Pure recall with no reasoning available. Q58 is a special case — see below.
Reading past the deciding word
3, 46, 51, 78, 82
25
“domestic”, “not”, “reducing”, “original
ancestor” — each sitting in the stem and each decisive.
Three distinctions and one reading habit account for every wrong answer on the paper.
The one that is not really an error
Q58, the age of the universe. The answer given was 20 billion years, which is
exactly what NCERT Class XII prints. The paper marked 13.8 billion correct, which is the
modern astrophysical figure.
Answering from the prescribed textbook is normally the right instinct for NEET, so this is
not a reasoning failure. The practical advice is to carry both numbers and know which source
each belongs to: if an option list offers 13.8 and not 20, take 13.8; if it offers both, the
paper is deliberately testing this, and 13.8 is the safer modern choice.
The single highest-value fix
Three questions — Q53, Q55 and Q81 — are the same question wearing different
clothes, and all three were answered “homologous”. Together they are worth 15 marks.
The test is one sentence: homologous means same ancestor and different jobs; analogous
means different ancestors and the same job. And a fast proxy: homologous pairs usually sit
inside one group (vertebrate and vertebrate), analogous pairs cross groups
(bird and insect, seal and penguin, squid and mammal).
The labels also travel in locked pairs — analogous always with convergent, homologous
always with divergent. In Q81 that alone eliminates half the options before the animals are
even considered.
Two habits to carry into the next paper
Test the chosen option forwards before moving on. In Q1, Q2 and Q22 a single Punnett
square would have exposed the mismatch in about ten seconds. The genetics was never the problem;
the absence of a check was.
In a “not” question, check the items you are keeping. Q82 asked which is
not a marsupial, and the most famous animal on the list was chosen. Reading the other
three — numbat, wombat, koala, all Australian — makes the Madagascan lemur obvious.